i need help please
2007-12-24 03:44:07 · 12 answers · asked by Anonymous in Education & Reference ➔ Homework Help
4x^2-36=0
(2x-6)(2x+6)=0
2x-6=0
2x+6=0
x=-3 or 3 but positive solution is 3
2007-12-24 04:41:17 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
3
2007-12-24 11:46:31 · answer #2 · answered by Anonymous · 1⤊ 1⤋
4x^2 - 36 + 36 = 0 + 36
4x^2 = 36
(4x^2) / 4 = 36 / 4
x^2 = 9
x = sq. root of 9 = 3
2007-12-24 11:48:51 · answer #3 · answered by BBQ 2 · 0⤊ 0⤋
I think the easiest way to see this is to isolate the variable by adding 36 to both sides of the equation...
4x^2 = 36
Further isolate by dividing both sides by 4.
x^2 = 9
Now you know why it can be 3 or -3. The POSITIVE solution would be the one without the negative symbol...
2007-12-24 12:16:01 · answer #4 · answered by Anonymous · 0⤊ 0⤋
4x^2-36=0
4x^2= 36
Divide both sides by 4.
x^2 = 9
take square root of 9
x= 3
2007-12-24 23:14:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋
4x^2-36 = 0
(2x-6)(2x+6) = 0
or x = 3 or x=-3
so positive soln is x=3
2007-12-24 11:47:42 · answer #6 · answered by jags20_us 2 · 0⤊ 1⤋
3
4(9)-36=0
2007-12-24 11:46:20 · answer #7 · answered by runfreexc 2 · 1⤊ 1⤋
move the -36 to the other side, then divide by 4, and then take the square root of that (which is +/- 9) and take the positive one.
2007-12-24 11:47:06 · answer #8 · answered by SpaceTrekkie 3 · 1⤊ 1⤋
1st you factor out the 4 so it is
4(x^2-9)
Then you factor out in between the brackets s it will be:
4(x-3)(x+3)
so x = 3 or x= -3
2007-12-24 11:48:59 · answer #9 · answered by Ray Ray 3 · 0⤊ 1⤋
X=3
or x=-3
2007-12-24 11:48:07 · answer #10 · answered by Anonymous · 0⤊ 1⤋