Jeremy has a fish tank that has a 40-cm by 70-cm rectangular base. The water is 25 cm deep. When he drops rocks into the tank, the water goes up by 2 cm. What is the volume in liters of the rocks?
2007-12-24 01:37:32 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the volume of the rock is:
4*7*0.2=5.6 liters
2007-12-24 01:43:06 · answer #1 · answered by the_black_pearl_vn 2 · 0⤊ 1⤋
1000cm3 = 1 litre
Volume of the water level that had risen = volume of the rock
Since the water level had risen by 2cm that is the height. The base length is 40 and the width is 70 cm. So
= 40*70*2
=5600 cm3
cm3 --> litres
5600 / 1000 =
5.6 litres
2007-12-24 09:51:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Find the difference in volume.
40 x 70 x 25 = 70,000 (no rocks)
40 x 70 x 27 = 75,600 (with the rocks)
Volume of rocks = 5600 cubic centimeters
Since 1 milliliter = 1 cubic centimeter
5600 milliliters
5.6 liters = volume of rocks in liters.
2007-12-24 09:46:33 · answer #3 · answered by Robert O 2 · 0⤊ 1⤋
40 x 70 x 2
= 2800 x 2
= 5600
= 5.6 litres
2007-12-24 12:04:15 · answer #4 · answered by An ESL Learner 7 · 0⤊ 0⤋
40 * 70 * 2 = 5600 cm^3= 5.6 liters
2007-12-24 09:44:48 · answer #5 · answered by mathman 3 · 0⤊ 1⤋
40 times 70 times 2 = 5600cm3
So you reduce it down to 5.6 liters.
2007-12-24 10:00:46 · answer #6 · answered by Chau D 2 · 0⤊ 0⤋