Solve please?

Question

5^y-1 = 25^2y-1

4^2t + 1 = 8^2t - 1

6^3x + 5 = 36^3x + 6

Answer 1

5^(y-1) = 25^(2y-1) (ln both sides )
(y-1)ln5=(2y-1)ln25
yln5 - ln5 = 2yln25 - ln25
2yln25-yln5 = ln25 - ln5
y(2ln25 -ln5)=ln25 - ln5
y=1/3

4^(2t+1)=8^(2t-1) (ln both sides )
(2t+1)ln4 = (2t-1)ln8
2tln4+ln4 = 2tln8 -ln8
2tln8-2tln4 = ln8+ln4
2t(ln8-ln4)=ln8+ln4
t=2.5

6^(3x+5)=36^(3x+6) (ln both sides)
(3x+5)ln6 = (3x+6)ln36
3xln6+5ln6=3xln36+6ln36
3xln36-3xln6 = 5ln6 - 6ln36
3x(ln36 - ln6)=(5ln6 - 6ln36)
x= -7/3

Answer 2

5^y-1 = 25^2y-1

25 = 5^2

so

5^y-1 = (5^2)^2y-1

5^y-1 = (5^4y-2

so y-1 = 4y-2

solve for y and u get y = 1/3



4^2t+1 = 8^2t-1

4 = 2^2
8= 2^3

so
(2^2)^2t+1 = (2^3)^2t-1

2^4t+2 = 2^6t-3

4t + 2 = 6t - 3

solve for t and u get t = 2.5


6^3x+5 = 36^3x+6

use the same method and u get x = -31/3

Answer 3

are you sure??

(5 to the y power) minus 1

or is it 5y - 1 = 25y^2 -1