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which expression represent the product of two consecutive odd integers, where N is and odd integer....

N(N+1), N(N+2), N(N+3), 2N+1....

If you can explain it that can help too. thanxx your help

2007-12-22 23:34:41 · 4 answers · asked by Anonymous in Education & Reference Homework Help

4 answers

1,2,3,4,5...
n is an odd integer. So n+1 must be even.
If you're not convinced look at the above numbers. Taking n = 1, we can clearly see that
n+1 = 1+1 = 2, which is even.
So, the number after 2 must be odd. Its 3. It can be represented as,
(n+1)+1 = 3, where n = 1
Now that can be written as
n+1+1 = n+2
1 and 3 are 2 consecutive odd integers. Their product is represented as
1 x 3
= n(n+2)

2007-12-23 00:04:13 · answer #1 · answered by Anonymous · 1 0

its n(n+2) , consecutive numbers are in the form n,n+1,n+2,n+3 so on but 2 consecutive odd numbers vud be n,n+2..so the product vill be n(n+2)

2007-12-23 07:46:23 · answer #2 · answered by Kelly 3 · 0 0

ok - half of a word problem is trying to figure out how to put it down on paper - - - - so

let's think about odd integers - - - - - 1 -3-5-7-9

what's common?? they ar +2 apart
and I cannot spel !!!! (time for bed)

so if we wanted 3 x 5 or 3(5)
and 3 = n
5 would equal n + 2

so I would pick
n(n+2)

and see - once we talk it through - - - - seems so easy

now you can do it

(BUT I hope u kin spel bettr) LOL!~!!!!!!!!!!!!

all the best (ZZZZZZzzzzzzzz......)

2007-12-23 07:45:58 · answer #3 · answered by tom4bucs 7 · 0 0

yeah it's n(n+2) i wont explain it again because their explanation is enough...i am not competing for points anyway...what important is we answer your question and helped you out...

2007-12-23 09:26:34 · answer #4 · answered by jhade0821 3 · 1 0

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