The cost of an adult ticket to a football game is $1.75. The cost of a student ticket is $ 1.25. Total receipts last week from ticket sales were $ 1700. If the number of students tickets sold was twice the number of adult tickets, how many of each type were sold?
Thank you for your help
2007-12-22 22:33:36 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Number of adult ticket = x
Number of student ticket = y
1.75x+1.25y = 1700
y=2x
1.75x+1.25(2x)=1700
1.75x+2.5x=1700
4.25x=1700
x=400
y=800
number of adult tickets = 400
number of student tickets =800
2007-12-22 22:36:45 · answer #1 · answered by Murtaza 6 · 1⤊ 0⤋
adults tickets were = 1700 /(2.50 + 1.75) = 400
and students tickets = 2 adult = 800
2007-12-22 23:08:17 · answer #2 · answered by sv 7 · 1⤊ 0⤋
letno. of tickets sold for adults is x
thn no. of tickets sold for students is 2x
now,
total revenue is 1700
and revenue generated by adult ticket is 1.75x
and revenue genetated by students ticket is 1.25(2x)=2.5x
therefore
1.75x + 2.5x = 1700
4.25x=1700
x=1700/4.25
x=400
now no. of adult ticket is 400 and no. of student ticket is 800
ok if its nt clear thn u can contact me
2007-12-22 22:41:40 · answer #3 · answered by rohit 1 · 1⤊ 0⤋
supose x is the number of adult tickets.Then 2x is the number of student tickrts.
1.75x+1.25(2x)=1.75 x+2.5x=4.25x
4.25=1700 so x=1700/4.25=400 and then 2x=800
2007-12-22 23:17:59 · answer #4 · answered by reza 4 · 1⤊ 0⤋
let no. of adult ticket be x
let no. of student ticket be y
then..
1.75x+1.25y = 1700
y=2x
1.75x+1.25(2x)=1700
1.75x+2.5x=1700
4.25x=1700
x=400
y=800
number of adult tickets = 400
number of student tickets =800
2007-12-22 23:02:52 · answer #5 · answered by knowledge 3 · 1⤊ 0⤋
Let n = the number of adults.
1.75n + 1.25(2n)=1700
1.75n + 2.50n = 1700
4.25n = 1700
n=400
400 Adults and 800 students.
QED
2007-12-22 22:42:35 · answer #6 · answered by Ken 7 · 1⤊ 0⤋