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Since lithium has a charge of 1+ and oxygen has a charge of 2-, the compound will be Li2O so that it has a neutral charge. The equation will be:
Li(s) + O2(g) = Li2O(s)
To balance it, we need two oxygens on the left side, so we put a 2 in front of Li2O:
Li(s) + O2(g) = 2Li2O(s)
Now we need four lithiums on the left side to balance it out:
4Li(s) + O2(g) = 2Li2O(s)
To do the net ionic equation, just show the elements as ions and each ion's charge:
4Li^+(s) + 2O^2-(g) = 2Li2O(s)
When you have a diatomic element like oxygen, just put the two in front of it so you can see that it's an ion.
You can see that the charges balance out.
Since there are no spectator ions in this equation, the total ionic equation is the same as the net ionic equation.

2007-12-22 13:47:36 · answer #1 · answered by anonymous 3 · 3 3

The reaction you are after is probably

4Li + O2 = 2 Li2O

However, Li does more slowly react with nitrogen (I think it is the only element to do so at room temperature):

6Li + N2 = 2 Li3N.

In both cases, there is no such thing as a separate net ionic equation because Li,O2,and N2 are used as neutral reagents, and the products, although ionic, are solids and not free-moving ions. You only use ionic equations when you are dealing with solutions.

2007-12-22 20:33:09 · answer #2 · answered by Facts Matter 7 · 5 2

a) sodium bisulphate + lithium hydroxide sodium bisulphate + lithium hydroxide --> sodium hydroxide + lithium bisulphate NaHSO4(aq) + LiOH(aq) --> NaOH(aq) + LiHSO4(aq) molecular equation already balanced I believe 1A group compound such as Na and Li are soluble salts so this reaction doesn't produce a precipitated product; therefore you don't need to write the net ionic equation because no reaction occurs. NaHSO4(aq) + LiOH(aq) --> No Reaction b) chromic acid (with one acid hydrogen ion) + rubidium hydroxide chromic acid's ionic name is hydrogen chromate, this will help in predicting the products for the molecular equation: hydrogen chromate + rubidium hydroxide --> hydrogen hydroxide + rubidium chromate H2CrO4(aq) + RbOH --> HOH(l) + Rb2CrO4(aq) Need to balance: H2CrO4(aq) + 2RbOH --> 2HOH(l) + Rb2CrO4(aq) ** HOH is water: H2O (just easier to balance as HOH) Break into ions, but keep H2O in tact because you only break (aq) substances into ions not (l), (s), or (g): 2H^1+(aq) + CrO4^2-(aq) + 2Rb^1+(aq) + 2OH^1+ --> 2Rb^1+(aq) + CrO4^2-(aq) + H2O(l) (this is the total ionic equation) notice that Rb and CrO4 are dissociated ions on both sides of the reaction, you can cross these out and leave the H, OH, and H2O 2H^1+(aq) + 2OH^1-(aq) --> 2H2O(l) reduce coefficients: H^1+(aq) + OH^1-(aq) --> H2O(l) this is the net ionic equation Good luck and I hope this helped.

2016-03-18 11:17:22 · answer #3 · answered by Anonymous · 0 0

The equation is Li + O2 = Li2O.
I'm not sure of the net ionic equation, though. You should be able to find it online.

2007-12-22 13:30:54 · answer #4 · answered by Reshma 2 · 0 2

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