Help with these math questions?

Question

Use the power rule and the power of a product or quotient rule to simplify the expression.
(4a)2

A 8a
B 16a2
C 8a2
D 16a


Simplify the following.
-5y0

A 0
B -4
C 1
D -5

Simplify the following.
(-6z2)(2z3)

A 12z6
B 8z5
C -12z5
D -12z6

Answer 1

[05]
(4a)^2
=(4)^2(a)^2
=16a^2

-5y^0
=-5*1
=-5

(-6z^2(2z^3)
=(-6*2)(z[2+3])
=-12z^5

Answer 2

I don't think you've identified the exponents correctly. I suspect that the first problem is (4a)^2. That answer is 16a^2. When squaring a combined term, all members of the term are squared.

I suspect the second problem is -5y^0. That answer is -5.
Think of it as -y^0-y^0-y^0-y^0-y^0.
Let me know if you want to understand why any number raised to the 0 power is 1. It's pretty simple.

I suspect that the third problem is (-6z^2)(2z^3). That answer is -12z^5

There are pretty simple rules that make this clear and you'll benefit greatly by practice.

Answer 3

1) (4a)^2
okay - we have to square both sides - our know number and our unknown
4x4 = ? and a x a = a^2

2) -5y0
sooooooooo easy - any thing times zero = ???????

confirming you meant -5 x Y x 0
or was it supposed to be -5 x Y^0
then anything to the zero power is 1
-5 times 1 (still easy)

3)almost same as #1 - multiply numbers to numbers - etc

-6 x 2 =
and when we multiply by exponents - we add them together
2+3= z?

all the best

Answer 4

(4a)2 = 16a2 (b)

-5y0 = -5 (d)

(-6z2)(2z3) = -12z5 (c)

Answer 5

a a c

Answer 6

1) B
2) D
3) C