Exponents Question?

1 ⤊

Divide: 24m^4n^2-8m^2n^3+4m^3n ÷ 4m^2n.

2007-12-22 11:47:43 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

[24m^4n^2-8m^2n^3+4m^3n] ÷ 4m^2n
= 4m^2n[6m^2n -- 2n^2 + m] ÷ 4m^2n
= 6m^2n -- 2n^2 + m

2007-12-22 12:00:24 · answer #1 · answered by sv 7 · 1⤊ 1⤋

24m^4n^2-8m^2n^3+4m^3n
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4m^2n

when you divide integers with exponents you subtract the exponents

answer is 6m^2n-2n^2+m

2007-12-22 13:52:39 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋

24m^4n^2 - 8m^2n^3 + m

2007-12-22 11:57:25 · answer #3 · answered by Anonymous · 0⤊ 2⤋

SV is right

2007-12-22 13:05:48 · answer #4 · answered by Anonymous · 0⤊ 0⤋