Really HARD math problem - HELP?

Question

Okaii, i know this sounds silly, but me and my friend are having a serious problem with like a grade 2 question.
So heres the thing:
Altogether we both had 22 chocolates.
I had the odd numbers(including 1) and she had the even.
But when she was suppose to eat the 22d, she gave it to me.
How many did we each have?
Now, logically you would think the ratio is 10:12 but wouldn't that mean that i had TWO more then her? Because the difference between 12 and 10 is 2. But i only had one extra. If i hadn't ate one more, we'd have had the exact same amount. So that would mean i had one more.
But what every one is telling us is that i had 12. LIKE I SAID! THAT WOULD MEAN I HAD TWO MORE!
Wtf! This is a serious question as silly as it sounds, so please answer seriously.
Thanks!

Answer 1

you: 1,3,5,7,9,11,13,15,17,19,21,22
her:2,4,6,8,10,12,14,16,18,20

she loses one, you gain one

|-1| + |1| = 2

so you would have two more than her

hope this helps :]

Answer 2

you had 12 she had 11

Answer 3

first, if there were 22 chocholates, you could not have had an odd number and her an even, because an even + an odd will always add up to an odd number.

Second, when you say that you BOTH had 22 chocholates, that implies that between you there were 44 chockolates (is this correct? because your answers imply that you had a total of 22 between both of you).

Lets assume there are a total of 22. The question must be stated that "before she was going to eat the 22nd she had had an even amount and you had an odd amount".

Assuming the above is true, there is still not enough to answer the problem, because each of the following would work.
2,20
4,18
6,16
...
18,4
20, 2
22,0

The last number assumes that 0 is considered an even number.

The answer is that not enough information has been given to get a unique answer.

Answer 4

You had #s,
1,3,5,7,9,11,13,15,17,19,21,22, which is 12...
and she had:
2,4,6,8,10,12,14,16,18,20...which is 10

so the ratio is 12:10 or 6:5, because you were both susposed to have 11, but she gave her one away whcih means she only had 10 (11-1=10) and you had one more than 11, (11+1=12)

So yes you did have 12.

I hope this helps.

Answer 5

12 and 10 is correct. When she gave you one, your number increased by 1 while hers decreased by 1. Those 2 changes produce a difference of 2.

Answer 6

Think of it this way: If a stranger had given you the chocolate, you would have 12 and your friend would still have 11. Since the chocolate came from your friend, you have 12 and she has 10.

Congratulations. You have learned the first lesson in double-entry accounting.

Answer 7

0 is a even number so you had 12 and she had 11

Answer 8

11 cause if yu count up the odds and evens its 11 both of them and if yu add 11+11=22 so the answer is 11