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Scott set up a volleyball net in his backyard. One of the poles, which forms a right angle with the ground, is 6 feet high. To secure the pole, he attached a rope from the top of the pole to a stake 4 feet from the bottom of the pole. To the nearest tenth of a foot, find the length of the rope.

a. 4.5 ft.
b. 3.2 ft.
c. 52 ft.
d. 7.2 ft

2007-12-22 10:24:34 · 7 answers · asked by mommawe'regoingtohell 1 in Science & Mathematics Mathematics

7 answers

Use the Pythagorean theorem. The rope is the hypotenuse of a triangle, where the legs are the 6 ft height of the pole and the 4 ft distance from the pole to the stake. The Pythagorean theorem states that a^2 + b^2 = c^2, so c = sqrt(a^2 + b^2), where c is the length of the hypotenuse and a and b are the lengths of the legs, 4 ft and 6 ft in this case. I find that the answer is d.

2007-12-22 10:28:30 · answer #1 · answered by DavidK93 7 · 0 0

This forms right angled triangle and length of rope is hypotenuse
sqrt(6*6 + 4*4)
= 7.2 ft

2007-12-22 10:28:31 · answer #2 · answered by jags20_us 2 · 0 0

You want to use the pythagarian theorem:

a^2 + b^2 = c^2

Where a and b are legs of a right triangle, and c is the hypotenus.

So one leg is 6ft, the other leg is 4ft, so let's plug those in:

6^2 + 4^2 = c^2
36 + 16 = c^2
52 = c^2

So to solve for c (the length of the rope) take the square root of both sides.
c = sqrt(52) = 7.21111 = 7.2

The answer is d.

2007-12-22 10:29:56 · answer #3 · answered by rebkos 3 · 0 0

this requires the use of pythagoras theorem(in a right triangle, (base)^2 + (perpendicular)^2 = (hypotenuse)^2.
the pole is the perpendicular of length 6 ft.
distance ofthe stake from bottom of pole is the base of length 4 ft.
and hypotenuse is the length of the rope which we need to find.
so, substituting in formula mentioned in the beginning:-
(length of rope)^2=(height of rod)^2 + (distance of stake from bottom of pole)^2
=>(length of rope)^2=(6^2)+(4^2)
=>(length of rope)^2=52
=>length of rope=sqrt(52)
=>length of rope = 7.2 ft

2007-12-22 10:35:30 · answer #4 · answered by Anonymous · 0 0

you can also use your common sense to answer this question.... the rope has to at least be longer than 6 ft because it is at a diagonal line and 52 feet is way off track so you can surmise the answer to be 7.2 ft

2007-12-22 10:34:20 · answer #5 · answered by Erica M 2 · 0 0

i might go nevertheless and do all the elementary ones on the multiple determination then do all the challenge fixing, then go returned to the multiple determination you skipped so in case you run outa time you wont lose too lots :)

2016-10-09 02:22:22 · answer #6 · answered by ? 4 · 0 0

the answer is d

2007-12-22 10:32:29 · answer #7 · answered by FliipHappy 4 · 0 0

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