If the mother has a gene for brown eyes and blue eyes and the father has a gene for brown eyes and hazel/green eyes, what are the chances that the offspring would have light or non-brown eyes?
2007-12-22 09:57:41 · 8 answers · asked by *EmmaSurella* 2 in Science & Mathematics ➔ Biology
The mothers parents have blue eyes and brown eyes. The father's parents have brown eyes and green/hazel eyes.
If that helps...
2007-12-22 10:30:45 · update #1
brown eyes is dominant, other non-brown eyes are recessive so we will make a punnet square
your mom = Bb
you dad =Bb
B= dominant (brown)
b= recessive (other)
multiply like this
.......B......b....
B...BB....Bb
b....Bb....bb
to have non-brwon eyes, the dominant allele (the big B) must not be present, and out of the four possilbe arangements of genes, this only happens once.
once out of foour times is 1/4 is 25%
so there is a 25 % chance it will happen
2007-12-22 12:01:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
It should be 50-50 because the mother has a gene for blue and the father has a gene for hazel/green eyes. Brown eyes are dominant but there are chances where it doesn't matter. Since there are two other genes that aren't brown it would be 50-50 but in some cases the brown will dominant no matter what because it is the dominant gene. You can use a punnett table to help you!
2007-12-22 20:13:15 · answer #2 · answered by ♥Jessica♥ 3 · 0⤊ 0⤋
Just looking at it I'd say 3:1 (as far as the non brown eyes are concerned). Or a 75% chance as you have to draw up a monohybrid cross and that leaves only three avalibiltys which is that the the colours other than brown aren't brown. But you have to take into consideration wether you have heterozygous or homozygous pairs of genes or wether each individual allel is recessive or dominant. With out that information your question can't really be answered.
2007-12-22 18:15:00 · answer #3 · answered by Anonymous · 1⤊ 0⤋
In eight children 1 blue 1 green and 6 brown eyes are predicted following this particular selection of alleles for the parents: brown Bb + blue gg x brown Bb + green Gg
Bbgg x BbGg =>
bbgg blue eyes 1/8 + bbGg green eyes 1/8 + BBGg or BbGg or BBgg or Bbgg brown eyed 6/8
If you want to play with the allele options this site is interactive for color of eyes.
http://www.athro.com/evo/gen/genefr2.html
EYCL1 (syn. Gey) - green/blue eye color - Gg
EYCL2 (syn. bey1) - central brown eye color gene
EYCL3 (syn. bey2) brown/blue - Bb
Dominance order between two genes
EYCL3 brown >EYCL1 green >EYCL3 blue = EYCL1 blue
See a detailed explanation for dominance order between brown green & blue
http://www.athro.com/evo/gen/eyecols.html
http://www.thetech.org/genetics/ask.php?id=203
2007-12-22 20:50:10 · answer #4 · answered by gardengallivant 7 · 0⤊ 0⤋
Are you assuming there is only 1 gene? There are more than one, though most is explained by one gene in some populations. the BEY locus is Brown/blue with brown dominant and GEY locus is Breen/Blue with Green dominant. However there are other loci involved.
http://www.ncbi.nlm.nih.gov/entrez/dispomim.cgi?id=227240
http://www.ncbi.nlm.nih.gov/sites/entrez?cmd=Retrieve&db=PubMed&dopt=AbstractPlus&list_uids=15262401
2007-12-22 20:03:47 · answer #5 · answered by Solanum 4 · 2⤊ 0⤋
I don't know but my husband and I are both blue eyes and both my girls have hazel eyes from my dad.
2007-12-22 18:05:42 · answer #6 · answered by Tigger 7 · 0⤊ 1⤋
you have to go beyond them and look at the grandparents and uncles and aunts
2007-12-22 18:06:37 · answer #7 · answered by nena 2 · 0⤊ 0⤋
not much of a chance at all....
try making a punnett square to find out
2007-12-22 18:01:26 · answer #8 · answered by Mandy 3 · 0⤊ 2⤋