Is Ron Paul the only one the Democrats think their candidate can beat?
2007-12-22 09:53:50 · 9 answers · asked by Anonymous in Politics & Government ➔ Politics
No, but he is the easiest one of them all to beat, mainly because he isn't a Republican and would thus attract few Republican votes.
2007-12-22 09:57:24 · answer #1 · answered by Anonymous · 2⤊ 6⤋
Hardly-none f the GOP hopefuls has a real chance of winning. However, there's winning and there's winning. A Democratic "landslide" would have a "coattail effect"--pulling more votes for Democratic candidates in other races. And if the GOP nominates Ron Paul--or Mike Hucaabee--it will guarantee a Democratic landslide. Either is way too far out on the fringes to draw the support of the mainstream voters.
2007-12-22 09:59:03 · answer #2 · answered by Anonymous · 3⤊ 2⤋
Actually if Ron Paul is not nominated and goes independent then its a sure win for Democrats.
Ron Paul is the only Republican candidate that can actually win.
2007-12-22 09:58:50 · answer #3 · answered by Edge Caliber 6 · 4⤊ 2⤋
because ron paul speak the truth.if its a race between ron paul and hillary i'll vote ron even though i'm a democrat
2007-12-22 10:00:16 · answer #4 · answered by tyler "god of typos" 5 · 5⤊ 0⤋
Wow- that's so funny..
I think it's because he's the only Republican they'd EVER dream of voting for, and he beats the hell out of any of the Democrat candidates. =)
2007-12-22 09:59:40 · answer #5 · answered by Anonymous · 4⤊ 1⤋
Because they all secretly want the best man in the white house...
Ron Paul 08!!
2007-12-22 09:59:12 · answer #6 · answered by MC 7 · 6⤊ 1⤋
He is the lesser of 8, oops... 7 evils.
2007-12-22 12:40:41 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Hillary will beat anyone the GOP puts up, so Dems don't care one way, or the other, who gets the GOP nomination. Paul would be the funniest, but will never get the nomination.
2007-12-22 09:59:34 · answer #8 · answered by Anonymous · 2⤊ 6⤋
Because he peddles liberal ideals.
2007-12-22 10:06:06 · answer #9 · answered by DOOM 7 · 1⤊ 2⤋