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7√x + 13 = 6

a. √7
b. 49
c. 1
d. no solution

2007-12-22 07:57:12 · 8 answers · asked by mommawe'regoingtohell 1 in Science & Mathematics Mathematics

8 answers

Subtract 13 from both sides

7 sqrt(x) = -7

divide by 7:

sqrt x = -1

If you square both sides, you'll get x=1. However, this is an extraneous solution, as this problem has NO solution.

that's it! :)

2007-12-22 08:02:41 · answer #1 · answered by Marley K 7 · 0 0

7 * sqrt(x) + 13 = 6
7 * sqrt(x) + 13 [-13] = 6 [-13]
7 * sqrt(x) = -7
7 [/7] * sqrt(x) = -7 [/7]
sqrt(x) = -1
sqrt(x) [^2] = -1[^2]
x = -1 * -1
x = 1

But I'm sure that the answer should be i somewhere. It involves the square root of a negative, or at least, was trying to.

2007-12-22 16:06:51 · answer #2 · answered by manualsearch 2 · 0 0

subtract 13 from each side. it leaves

7 root x = -7

divide both sides by 7, leaves

root x =-1

what number times itself gives -1? Any number multiplied by itself will always be positive, so there is no solution, d)

2007-12-22 16:02:09 · answer #3 · answered by Anonymous · 0 0

1. add 13 to both sides get
7sqrt(x)=(-7)
2. divide by 7 and get
sqrt(x)=-1
3. square both sides to clear the sqaure root and get
x=1
4 therefore the answer is c

2007-12-22 16:05:21 · answer #4 · answered by shadowca1964 4 · 0 0

I would say C but dont quote me!! Good Luck!

2007-12-22 16:01:27 · answer #5 · answered by wats2004 2 · 0 0

x = i*root(7) , i = root(-1)

2007-12-22 16:01:28 · answer #6 · answered by Nur S 4 · 0 0

no . solution

2007-12-22 16:04:20 · answer #7 · answered by cattbarf 7 · 0 0

i have absolutely no idea.....


bt im goin to say.....

D

2007-12-22 16:01:16 · answer #8 · answered by Tinkerbell <Dakota> 1 · 0 0

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