What is the vertex of y = 2(x - 3)^2 + 1?

Answer 1

Vertex is V(3 , 1)

Answer 2

Dear Mr. Cody.

The vertex of your quadratic equation ( which happens to be a parabola) is as follows:

y = 2 ( x - 3 )^2 + 1
y - 1 = 2 ( x - 3 )^2
y - K = 4p ( x - h )^2 -----> standard form of the equation of the parabola.

The vertex is ( h , k ) = ( 3 , 1 )

Answer 3

A parabola in the form y = a(x - h)^2 + k has vertex

(h, k)

Therefore, the above parabola's vertex is

(3, 1)

Answer 4

This equation is already in vertex form, so you can read it straight from the equation.

The vertex is (3, 1)

Take the number inside the bracket with the opposite sign to get the x coordinate, and take the number at the end to get the y coordinate.

Technically to find the x coordinate, solve for x - 3 = 0

x - 3 = 0
x = 3

Answer 5

Vertex form of a parabola:

y=a(x-h)^2+k

The vertex is at (h,k).

So in this particular parabola the vertex is at (3,1)