x = [- 6 ± √196 ] / 2
x = [- 6 ± 14 ] / 2
x = 4 , x = - 10
OR
(x + 10)(x - 4) = 0
x = - 10 , x = 4
2007-12-25 07:27:17
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answer #1
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answered by Como 7
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x² + 6x - 40 = 0
roots of the equation = (-b ± √(b² - 4ac) /2a where a, b and c are coefficients of x² , x and the constant.
a = 1
b = 6
c = -40
(-6 ± √((6)² - 4(1)(-40)) /2(1)
(-6 ± √((36 +160)) /2
(-6 ± √(196)) /2
(-6 ± 14) /2
roots are (-6 + 14)/2 and (-6 -14)/2
= 8/2 and -20/2
= 4 and -10
~~~
2007-12-22 04:30:55
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answer #2
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answered by A Little Sarcasm Helps 5
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Hey there!
Here's the answer.
-b±sqrt(b^2-4ac)/2a --> Write the Quadratic Formula.
-6±sqrt(6^2-4(1)(40))/2(1) --> Substitute 1 for a, 6 for b and -40 for c.
-6±sqrt(36+160)/2 --> Simplify.
-6±sqrt(196)/2 --> Add 36 and 160.
(-6±14)/2 --> Evaluate sqrt(196).
-3±7 --> Reduce the fraction.
-3+7 or -3-7 --> Replace ± with a + and a -.
4 or -10 Simplify each expression.
So the answer is x=4 or x=-10.
Hope it helps!
2007-12-22 04:32:36
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answer #3
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answered by ? 6
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6^x2+8x+1=0 With comparison to the standard form of ax^2+bx+c=0 we have: a=6 b=8 c=1 delta=b^2-4a= 64 - 24= 40 x=(-b+-sqrt(delta))/2a= (-8-+2sqrt(10))/12 => x1= {sqrt(10)-4}/6 = - 0.13962 x2= {-sqrt(10)-4}/6 = - 1.19371
2016-04-10 12:55:57
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answer #4
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answered by Anonymous
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x^2 + 6x - 40 = 0
(x + 10)(x - 4)=0
x= -10 and x=4
2007-12-22 19:19:10
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answer #5
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answered by Santiago 3
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x^2 + 6x - 40 = 0 can be easily factored by noting that factors of 40 (like 10 and 4), can subtract to give 6.
(x + 10)(x - 4) = 0
so x = -10 and x = 4 are your two roots of the equation.
2007-12-22 04:33:42
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answer #6
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answered by Charles M 6
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Given:
x^2 + 6x – 40 = 0
product, ab =-40
sum, a + b = +6
Therefore a= +10 and b = -4
x^2 +10x - 4x– 40 = 0
x(x +10) -4 (x + 10) =0
(x - 4) (x + 10) =0
=> x =4 or x=-10
all the best
2007-12-22 04:30:58
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answer #7
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answered by Roslyn** luv maths 2
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a = 1
b = 6
c = -40
Quadratic formula = (-b ± √(b²-4ac))/2a
Now, plug in the values for a, b, and c:
(-6 ± √(36 + 160))/2
(-6 ± √(196))/2
√(196) = 14
(-6 ± 14)/2
-3 ± 7
So the answers are -10 and 4
2007-12-22 04:30:33
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answer #8
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answered by Anonymous
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x^2 + 6x - 40 = 0
x^2 +10x - 4x - 40 = 0
x(x+10) - 4(x+10) = 0
(x+10)(x-4)=0
x = -10 and x = 4
2007-12-22 04:32:37
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answer #9
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answered by ▐▀▀▼▀▀▌ ►MARS◄ ▐▄▄▲▄▄▌ 6
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x2 + 6x – 40 = 0
x = [-b +- sqrt(b^2 - 4ac)]/2a
x = [-6 +- sqrt(36 + 160)]/2
x = [-6 +- sqrt(196)]/2]
x = [-6 +- 14]/2
x = -3 +- 7
x = -10, 4
2007-12-22 04:32:38
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answer #10
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answered by Anonymous
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