3(4 - 2x) = 6(x + 2) x=?

Answer 1

12 - 6x = 6x + 12
12 x = 0
x = 0

Answer 2

Left side:
3(4 - 2x) = 12 - 6x

Right side:
6(x + 2) = 6x + 12

12 - 6x = 6x + 12
Add 6x to each side:
12 = 12x + 12
Subtract 12 from each side:
12x = 0
Divide by 12:
x = 0

@Ken:
There isn't a second x on the right; the asker has it as a seperate comment "x=?" to ask for the value of x

Answer 3

Aha, let's see:
First, let's make those expressions as simple as possible:
3(4-2x) = 3(4) - 3(2x) = 12 - 6x
6(x+2) = 6x+ 6(2) = 6x + 12

Now, let's combine like terms:
12-6x=12+6x
12-6x-6x=12
-6x-6x=12-12
-6x-6x=0
-12x=0
x=0

CHECK:
3(4-2[0])=3(4)+3(2[0])=12+3(0)=12+0=12
6(0+2)=6(2)=12
I'm right waalhamduleEllah.




P.S.
You might find it even easier if you factor the two polynomials:
12-6x
3*2*2 Vs 2*3*x
2*3=6
GCF=6
6(2)+ -1[6(x)]
6(2)+-6x

12+6x
3*2*2 Vs 2*3*x
2*3=6
GCF=6
6(2)+6(x)

Answer 4

---- 3(4 – 2x) = 6(x + 2)
12 – 6x = 6x + 12
12 x = 0
x = 0

Answer 5

3(4 - 2x) = 6(x +2)
12 - 6x = (6x +12)
-6x -6x = 12 - 12
-12x = 0
x = 0

Answer 6

Expand brackets:
12-6x=6x+12
Add 6x to both sides:
12=12x+12
Subtract 12 from both sides:
0=12x
Divide both sides by 12:
0=x

Answer 7

12 - 6x = 6x + 12
0

Answer 8

Colleagues,

Aren't there two x's on the right?

First expand each side:

12-6x = 6x^2 + 12x

Then combine like term
12= 6x^2 +18x
Isn't it a quadradic?

6x^2 +18x -12 = 0

Answer 9

12-6x=6x+12
+6x =6x
12=12x+12
-12
12=12x
/12 /12
0=x

Answer 10

12-6x=6x+12
12x=0
x=0