[01]
7-[13-{12-6(6 of -5)}]
=7-[13-{12-6(-30)
=7-[13-{12+180}
=7-[13-192]
=7-[-179]
=7+179
=186
2007-12-22 02:20:33
·
answer #1
·
answered by alpha 7
·
0⤊
0⤋
Break it down-
You always have to do the (brackets) [ ] 1st:
This is the problem you are dealing with [13 - {-2 - 6 (6 of -5)}]
So within that you must start with the { } Next:
This is then the problem you are dealing with {-2-6 (6 of -5)}
Now it is starting to look a little easier-
Next you have to break it down more to the ( ):
That leaves you with (6 of -5)
And your answer to that is (-30)
Now insert that into the problem so it would then look like:
7 - [13 - {-2 - 6 (-30)}] =
Now we go backwards the the problem before this one:
{-2-6 (-30)} that looks easier
Do the calculations and you get : 178
Put that problem 7 - [13 - 178]
Then do the brackets [13 - 178]
You get -165
What your left with is 7 - -165
and i think you can take it from there..... :)
Just in case not the answer is 172
2007-12-22 02:51:04
·
answer #2
·
answered by what_name_isnt_used34 2
·
0⤊
0⤋
Following Order of operations: EPMDAS
Since there are no exponets we first do Parentheses
Step 1: 7 - [13 - {-2 - 6 (6 of -5)}]
Then we multiply
Step 2: 7 - [13 - {-2 - 6 (-30)}]
Then in the inner Parentheses we add
Step3: 7 - [13 - {-2+180}]
Now we Subtract
Step 4: 7 - [13 - {178}]
Subract (remember when subtracting a negative number we are really adding)
Step 5: 7 - [-165]
172
There is the proof:
hope this helps. Its my best work considering it was in my head while stuck in traffic.
2007-12-22 02:38:32
·
answer #3
·
answered by Jonathan R 3
·
0⤊
0⤋
----- 7– [13 – {– 2– 6(6 of – 5)}] ---------- of means multiplication i.e. 6 Ã (– 5) = – 30
=7– [13– {–2– 6(– 30) ----------- (– 6)Ã (–30) = + 180
=7– [13– {–2+180} --------- –2 + 180 = 178 but outside bracket (– )sign is there so after opening bracket +180 will become – 178
= 7– [13– 178] ----------- 13 – 192 = – 179 but again – sign outside bracket.
= 7– [– 165]
= 7+165
= 172
2007-12-22 02:30:19
·
answer #4
·
answered by Pranil 7
·
0⤊
0⤋
Solve first the expression inside a grouping symbol:
"inside ,, outward! "
7-[13-{12-6(6 of -5)}]
7-[13-{12-6(-30)
7-[13-{12+180}
7-[13-192]
7-[-179]
7+179
186
2007-12-22 02:11:05
·
answer #5
·
answered by RYAN 3
·
0⤊
0⤋
7 - {13 - [-2 - 6 (6 of -5)]}
= 7 - {13 - [-2 - 6 (-30)]}
= 7 - {13 - [-2 - (-180)]}
= 7 - {13 - [-2 + 180]}
= 7 - {13 - 178}
= 7 - (-165)
= 7 + 165
= 172
2007-12-22 03:23:30
·
answer #6
·
answered by An ESL Learner 7
·
0⤊
0⤋
do the innermost brackets FIRST, then work OUTWARD.
7-[13-{-2-6(6*-5)}]
7-[13-{-2-6*(-30)}]
7-[13-{-2+180}]
7-[13-178]
7+165
and sarkar05, you put 12 instead of -2
answer=172
2007-12-22 02:27:04
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
Order of operations:
7 - [13 - {-2 - 6 (6 of -5)}]
7-[13-{-2-6 (-30}]
7-[13-{-8(-30)}]
7-[13-{240}].....................
......
2007-12-22 02:19:14
·
answer #8
·
answered by iluvkatmcphee 2
·
0⤊
0⤋
EASY peeesyy.
first you do the brackets.. TEH MOST INNER ONES.
do 6of -5 and then multiplythat by 6 and do -2- the answer and then subtract 13 from the answer.. and then subtract 7 and then you got it.
2007-12-22 02:13:50
·
answer #9
·
answered by K i r a n, 2
·
0⤊
0⤋
-2
2007-12-22 02:13:02
·
answer #10
·
answered by rajat jain 3
·
0⤊
0⤋