According to the song, on the 1st day you get a partridge in a pear tree. On day 2, you get 2 turtle doves AND a partridge in a pear tree, thus now having 2 turtle doves and TWO partridges. So at the end of the 12th day, how many of each would you have?
2007-12-20 15:43:43 · 5 answers · asked by Joe M 3 in Education & Reference ➔ Trivia
364 items
12 Partridges in a pear tree
22 Turtle Doves
30 French hens
36 Calling birds
40 Golden rings
42 Geese-a-laying
42 Swans-a-swimming
40 Maids-a-milking
36 Ladies dancing
30 Lords-a-leaping
22 Pipers piping
12 Drummers drumming
2007-12-20 15:54:00 · answer #1 · answered by DodgerDave 6 · 0⤊ 0⤋
12 Partridges in Pear Trees
22 Turtle Doves
30 French Hens
36 Calling Birds
40 Golden Rings
42 Geese a laying
42 Swans a swimming
40 Maids a milking
36 Ladies dancing
30 Lords a Leaping
22 Pipers Piping
12 Drummers Drumming
2007-12-20 23:57:02 · answer #2 · answered by Kris W 2 · 0⤊ 1⤋
12 Ps in PTs
11 x 2 = 22 TD
10 x 3 = 30 FH
9 x 4 = 36 CB
8 x 5 = 40 GR
7 x 6 = 42 GaL
6 x 7 = 42 SaS
5 x 8 = 40 MaM
4 x 9 = 36 LD
3 x 10 = 30 LaL
2 x 11 = 22 PP
1 x 12 = 12 DD
2007-12-20 23:53:43 · answer #3 · answered by Beardo 7 · 0⤊ 0⤋
You would have:
12 partridges
22 turtle doves
30 hens
36 calling birds
40 rings
42 geese
42 swans
40 maids
36 ladies
30 lords
22 pipers
12 drummers
So you would have a total of 364 gifts..
2007-12-21 00:01:45 · answer #4 · answered by lunarequator 1 · 1⤊ 0⤋
He would have given 364 gifts
1
3
6
10
15
21
28
36
45
55
66
+78
364
2007-12-21 09:48:08 · answer #5 · answered by softballsoccerq 2 · 0⤊ 0⤋