According to the song, on the 1st day you get a partridge in a pear tree. On day 2, you get 2 turtle doves AND a partridge in a pear tree, thus now having 2 turtle doves and TWO partridges. So at the end of the 12th day, how many of each would you have?
2007-12-20 15:43:21 · 7 answers · asked by Joe M 3 in Science & Mathematics ➔ Mathematics
Twelve drummers drumming = 1*12 = 12
Eleven pipers piping = 2*11 = 22
Ten lords a-leaping = 3*10 = 30
Nine ladies dancing = 4*9 = 36
Eight maids a-milking = 5*8 = 40
Seven swans a-swimming = 6*7 = 42
Six geese a-laying = 7*6 = 42
Five golden rings = 8*5 = 40
Four calling birds = 9*4 = 36
Three French hens = 10*3 = 30
Two turtle doves = 11*2 = 22
Partridge in a pear tree! = 12*1 = 12
Total number of gifts over 12 days = 364
2007-12-20 15:56:54 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
12 Partridges in Pear timber 22 Turtle Doves 30 French Hens 36 Calling Birds 40 Golden jewelry 40 two ducks a laying 40 two Swans a swimming 40 Maids a milking 36 women dancing 30 Lords a leaping 22 Pipers Piping 12 Drummers Drumming
2016-10-02 05:04:21 · answer #2 · answered by ? 4 · 0⤊ 0⤋
78
2007-12-20 15:51:53 · answer #3 · answered by Ummm...... 4 · 0⤊ 1⤋
If it were the serial total (one instance of each), the answer would be:
78
However, the way you worded the question, it would be a compounded total, so the answer would be:
364
2007-12-20 15:57:28 · answer #4 · answered by pixelprotagonist 1 · 0⤊ 1⤋
78?
2007-12-20 15:53:11 · answer #5 · answered by keb 2 · 0⤊ 1⤋
None as we are not Christians.
2007-12-20 15:47:02 · answer #6 · answered by Madhukar 7 · 1⤊ 1⤋
66!?!?!?! im not xur with that
2007-12-20 15:51:07 · answer #7 · answered by emoÜ 2 · 0⤊ 1⤋