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For example, if the 6 numbers were 1, 2, 3, 4, 5 and 6, how many different sequences can you make before they eventually repeat each other?

2007-12-20 15:09:17 · 2 answers · asked by Mat C 1 in Science & Mathematics Mathematics

2 answers

Factorial. n! = n x n-1 x n-2 x ... x 1

The number of ways n unique objects can be arranged is n!

So, for 6 numbers, the number of arrangements is 6 x 5 x 4 x 3 x 2 x 1 = 720.

That's why it gets so hard to unscramble jumbled words once they pass this size, so many combinations.

2007-12-20 15:16:42 · answer #1 · answered by roderick_young 7 · 1 0

about 50. why do you think it's so hard to win the lottery?

2007-12-20 23:17:41 · answer #2 · answered by gen patton 6 · 0 0

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