Somebody factor x(a+b)+x(a+c). (please explain the whys and hows and its even better if you give examples)?

Answer 1

(x) (a + b + a + c)
(x) (2a + b + c)

Answer 2

Factor x out.
x[(a+b) + (a+c)]
Remove the parentheses.
x(a+b+a+c)
Add.
x(2a+b+c)

It is the same as Mika's answer, except not distributed.

An example:
2(1+2) + 2(1+3)
2(1+2+1+3)
2(2 times 1 +2+3)
In this case, 1=a

Hope this helps you!

Answer 3

Here, there are two terms, x(a + b) and x(a + c).
Observe what is a common factor and you find x.
Take x common from the two and add the remaining factors in a bracket.
Thus,
x(a + b) + x (a + c)
= x(a + b + a + c)
=x(2a + b + c).

Answer 4

You must factor by pulling out the GCF first.
So, both terms have x being used in multiplication, hence GCF is x. Note: ax + ay = a(x +y) treat (a+b) and (a+c) just like you would the x and y in the simpler version stated.
x[(a + b) + (a + c)]
=x[a + a + b + c] drop the parentheses and add like terms.
=x(2a + b + c)
Hope this helps.

Answer 5

x(a + b) + x(a + c)
xa + xb + xa + xc
2xa + xb + xc
let a = 1 , b = 2 , c = 3
2x(1) + x(2) + x(3)
2x + 2x + 3x
7x
factor are needed to make life easy

Answer 6

Hi,

If I understand you right, you have to open the brackets first and find the same light terms...

x(a+b)+x(a+c)=ax+bx+ax+ac=2ax+bx+cx

For example,
3x(x+3)+4x(5+5x)=3x^2+9x+20x+20x^2=23x^2+29x

All the best,
Mika

Answer 7

xa + xb + xa + xc
= 2xa + xb + xc
= x (2a + b + c)

Answer 8

2ax+bx+cx