1. a sqrt -3 sqrt 2a^2
2. sqrt 7 multiplied by sqrt 14
2007-12-20 15:07:18 · 4 answers · asked by God Bless America!~ 4 in Science & Mathematics ➔ Mathematics
a sqrt -3 * 2a^2=
since you are dealing with imaginary numbers here because of sqrt -3= i sqrt 3 * a sqrt 2
sqrt 7 * sqrt 14= sqrt 98=sqrt 49 sqrt 2= 7 sqrt 2
2007-12-20 17:10:01 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
1.) If this is sqrt(-3)*sqrt(2a^2), then
i*sqrt(3)*a*sqrt(2).
If this is sqrt(-3)*sqrt(2a)^2, then
i*sqrt(3)*2a.
Either way, the result is a nonreal answer. If you haven't covered i or imaginary numbers yet, put down "no real answer" on your paper.
2.) sqrt(7)*sqrt(14)
Multiply what is inside each radical.
sqrt(7*14)=sqrt((7^2)*2)=7sqrt(2)
This one produces a real answer.
2007-12-20 23:15:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
49 * 196 = 245
2007-12-20 23:11:47 · answer #3 · answered by Hammad Khan 2 · 1⤊ 0⤋
1. u didnt put the question properly
2. 9.899494937
2007-12-20 23:11:15 · answer #4 · answered by 2Shoes 2 · 0⤊ 1⤋