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A 1.00×104kg railroad car is rolling at 6.00m/s when a 8000kg load of gravel is suddenly dropped in.

Kevin is standing on a sheet of ice that covers the football stadium parking lot in Buffalo, New York; there is negligible friction between his feet and the ice. A friend throws Kevin a ball of mass 0.400kg that is traveling horizontally at 10.0 m/s. Kevin's mass is 67.4 kg. If Kevin catches the ball, with what speed v(f) do Kevin and the ball move afterward? I got this right, which was 5.9 cm/s, but I don't understand how to get the second part: If the ball hits Kevin and bounces off his chest horizontally at 7.50 in the opposite direction, what is his speed v(f) after the collision?

2007-12-20 14:20:30 · 3 answers · asked by nothankyou1110 2 in Science & Mathematics Physics

3 answers

Momentum is conserved!

Calculate the momentum change of the ball: (10.0 m/s- -7.50 m/s) X 0.400kg .

Set Kevin's momentum change equal in magnitude, but opposite in direction, to that of the ball.

2007-12-20 16:01:11 · answer #1 · answered by Tim C 7 · 0 0

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2016-12-18 06:05:02 · answer #2 · answered by Erika 4 · 0 0

use the formulas for an inelastic collision.

2007-12-20 14:28:15 · answer #3 · answered by 4Brain 4 · 0 1

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