Someone please please help me!! i'm desperate i need to know how to do this problem!! thanks?

Question

A m1 = 4.80 kg block on a smooth tabletop is attached by a string to a hanging block of mass m2 = 2.30 kg, as shown in Figure 6-29. The blocks are released from rest and allowed to move freely.

the figure is at this url.... http://www.webassign.net/walker/06-29alt.gif

Find the Acceleration of the blocks and the tension in the string
-->acceleration should be in m/s^2
-->tension should be in newtons


If you could solve this it would be much appreciated!! thanks

Answer 1

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On a smooth tabletop, m1 = 4.80 kg

Mass of hanging block ,m2 = 2.30 kg,

The blocks are released from rest and allowed to move freely.

Weight of habging block = m2g =2.3*9.8=22.54 N

The mass m1 on the table is accelerated by tension 'T' in the string

If acceleration of system = a

T = m1a

m2g -T =m2a

a =m2g /(m1+m2)

a =22.54 /7.1=3.1746 m/s^2

T =m1a=4.8*3.1746

T=15.238 N

Acceleration of the blocks is 3.1746 m/s^2 and the tension in the string is 15.238 N
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Answer 2

Ok,
First, lets find the tension in the string. The tension is caused by m2 which is subject to the acceleration of gravity.
F = ma where m = 2.3 kg and a = 9.8 m/sec^2
F = 22.54 kg*m/sec^2 = 22.54 Newtons
So the net force acting on the 2 masses is 22.54 Newtons
The total mass of the system is m1+m2 = 7.1 Kg
Again F=ma but now F = 22.54 Newtons and m = 7.1 Kg, solve for a. 22.54 = 7.1 * a
a = 3.17 m/sec^2

Answer 3

You have the weight of one block having to accelerate both blocks so:
a = 9.8m/s^2 X [2.30 / ( 2.30 + 4.80)]

To calculate the tension consider the acceleration of m1 and use F = ma.

Answer 4

First you need to identify the forces acting on the blocks:
There is force of gravity on both of them, but on M1 it cancels out with the normal force.
So the only force that is causing the system to move is the force of gravity on M2.

M2 * 9.8 = (M1 +M2)a
(2.3)(9.8) = (7.1)a
22.54 = 7.1a
a = 3.17 m/s/s

The force that the block acts on the string is equal to that of the Fg on the block . In order to find the tension in the cord, you only need to multiply the mass of M2 times the acceleration of gravity

M2 * 9.8 = 22.54
F = 22.5 N

Answer 5

Its just sum of the forces in x direction and sum of the forces in y direction. Theres friction and tension in x, and weight of blocks and tension of string in y. I think that is everything now its your turn.

Answer 6

for the acceleration you multiply the 2nd mass times gravity (9.81 m/s^2). and for the tension you solve for the vectors using the pythagoream thereom, which would be 1st mass squared times 2nd squared....and square root the product of this multiplication.........i'd give u the answers if i had a calculator

Answer 7

wahat