centripetal force physics problem?

Question

ok so in this scenario.... wat forces are involved and where?

ok so a boy whirls a block from directly above his head and releases it right when his arm is perpendicular to the ground....

ultimaltly i want to calculate the final velocity of the block as it leaves the boy's hand... but i want to make sure that i take all forces into account before calculating....

thank you

if anyone cod actually giv an answer with juss variables for specific values, it will b great...

thank you very much!

Answer 1

The initial velocity is
V=at where acceleration a is a sum oc centripetal acceleration ac and acceleration due to gravity
a= ac + g

since t=o at the time it is released its initial velocity downward is V=0.

However it has a velocity. It is the tangential component Vt responsible for centripetal acceleration ac
ac= (Vt)^2/R r\where R is the radius of the rotation of the block.

Answer 2

the 1st one isn't actual a Centripetal rigidity problem. that's a Newton's familiar regulation of Gravitation problem. merely use the formulation : acceleration via gravity = (G x mass of earth or the planet) / (a million.5 x radius of earth)^2 the 2d is yet another NULG problem, yet with a given top faraway from the earth's floor. Use: acceleration via gravity = (G x mass of earth) / (radius of earth + 580000 m)^2 the cost of G (gravitational consistent) in our image voltaic gadget is 6.sixty seven x 10^-11 Nm^2/kg have in mind the customary values: Newtons, meters, and kilograms. The 0.33 one is approximately centripetal rigidity. acceleration via gravity in the worldwide = velocity of satellite tv for pc^2 / radius of earth Deriving: velocity = sq. root of (acceleration x radius) acceleration via gravity in the worldwide = 9.8 m/s^2