Solve using the quadratic formula 4x^2+7x+5=0?

Answer 1

4x² + 7x + 5 = 0
x = -7/8 ± [√(49 - 80)]/8
x = -7/8 ± [√(-31)]/8
x = -7/8 ± i[√(31)]/8

Answer 2

4x^2+7x+5=0:
The quadratic formula general solution is
x=(-b +/- sqrt(b^2-4*a*c))/(2a) where in
your case a=4, b=7, and c=5.

Substitute these values as
x=(-7 +/- sqrt(7^2-4*4*5))/(2*4)
x=(-7 +/- sqrt(49-80))/8
x=(-7 +/- sqrt(-31))/8

Since the square root is negative,
your solutions are imaginary using
i=sqrt(-1).

Thus, x=(-7 + i*sqrt(31))/8 and
x=(-7-i*sqrt(31))/8.

For more solutions and information plug
in values at http://www.1728.com/quadratc.htm

Answer 3

-7 + or - sqrt 7^2 - 4(4)(5) over 8