universal gravitation 2 ???

Question

An astronaut weighs 8.00 x 10^2 newtons on the surface of Earth. What is the weight of the astronaut 6.37 x 10^6 meters above the surface of Earth?

plz show work!!

Answer 1

its weight will be as following.

first we can get the mass of the astronaut which is constant.

m = w / g

m = 8E2 / 9.8 = 81.6 kg

also we recall that the earth radius is
r = 6.37E6 m

which is same as the altitude given in the problem

so, if we know that the gravity at the earth surface is = 9.8 m/s²
then it will be decreased to the half for an altitude equal to the radius of the earth.

g' = 9.8 / 2 = 4.9 m/s² @ altitude =6.37E6

and now we can multiply the mass of the astronaut
by the g' to get the weight @ altitude =6.37E6

W = m * g'

W = 81.6 * 4.9 = 399.8 N



Good luck

Answer 2

200 Newtons Relative between the astronauts and the Earth.The ratio of the Astronaut weignt in space at one Earth diameter away relative to earth center is therefore 25% of the weight he had on the surface of the Earth.
The reason is at that altitude the acceleration is one quarter "g".
The space pressure that holds and keeps together the astronauts in constant shape and structure is equal to the product of the Astronaut's mass density at that elevation and the speed of light square squared.

This is the only simple answer that i could give. Hope this helps your undertanding of Gravity Field.