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A 0.013-kg ball is shot from the plunger of a pinball machine. Because of a centripetal force of 0.02 N, the ball follows a circular arc whose radius is 0.47 m. What is the speed of the ball?

thank you

2007-12-20 09:49:13 · 2 answers · asked by Mr. Tambourine Man 3 in Science & Mathematics Physics

2 answers

centripetal force is described as:

F=mv^2/r

you are given F, m and r, so solve for v:

v=sqrt[Fr/m]=sqrt[0.02*0.47/0.013]
=0.85 m/s

2007-12-20 09:52:50 · answer #1 · answered by kuiperbelt2003 7 · 1 0

Centripetal force is F = mv^2 / r, where m is mass, v is velocity, and r is radius. You've been given F, m, and r, so you can solve algebraically for v.

2007-12-20 09:51:34 · answer #2 · answered by DavidK93 7 · 3 0

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