solve using square root method -9(x-3)^2=-7?

Answer 1

Divide both sides by -9

(x-3)² = 7/9

Take the square root of both sides:

x - 3 = ±√(7 / 9)

x = √7 / 3 + 3
OR
x = -√7 / 3 + 3

x = 3.881917104 OR x = 2.118082896

Answer 2

x= to square root of 7/9 plus 3

Answer 3

Cubic Equations
Let's say you have the equation ax3 + bx2 + cx + d = 0. The first thing to do is to get rid of the "a" out in front by dividing the whole equation by it. Then we get something in the form of x3 + ex2 + fx + g = 0. The next thing we do is to get rid of the x2 term by replacing x with (y - e/3). The new equation y3 + py + q = 0 has no y2 term. This is much easier to solve, although it's still kind of hard and it took a lot of really smart people a long time to do.

Answer 4

i will use this image for sq. root: { First, we are in a position to alter x to ({x)^2 Then we could have: {x = 12 - ({x)^2 as a results of fact {x is 12 - x (from the question itself), we substitute all {x to twelve - x. we are able to now have: 12 - x = 12 - (12 - x)^2. increasing this equation provides you with 12 - x = 12 - (one hundred forty four - 24x + x^2) 12 - x - 12 +one hundred forty four - 24x -x^2 = 0 x^2 - 25x + one hundred forty four = 0 (x - sixteen)(x - 9) = 0 So, x=sixteen, or x=9

Answer 5

(x-3)^2 = -7/-9 = 7/9
x-3 = +/- sqrt(7)/3
x = 3 +/- sqrt(7)/3

Answer 6

-9(x-3)2=0.7
-18x+54=0.7
54-0.7=18x
53.3=18x
x=2.96111111111

Answer 7

you cant