Assuming the Law of Universal Gravitation F(g) = (GMm/r^2)(-r), apply the acceleration of gravity at the Earth's surface, the radius of the Earth, and the radius of the moon's orbit to calculate the acceleration of the moon.
2007-12-20 08:45:34 · 2 answers · asked by sapphireleech@sbcglobal.net 2 in Science & Mathematics ➔ Physics
This is just a ratio of the earth's radius and the radius of the moon's orbit -- all to the r^2.
Newt's Law of Gravity: F=GMm/r^2
also, F=ma
F.you = m.you*g =GMm.you/r.earth^2
g=GM/r.earth^2
F.moon = m.moon*a =GMm.moon/r.moon^2
a.moon=GM/r.moon^2
therefore,
a.moon=g * r.earth^2/r.moon^2
Should be ~ 2.7x10^-5 m/sec^2
2007-12-23 02:05:27 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 1⤊ 0⤋
Find the mass of the moon and the radius.
Answer is 1.62 m/s2
2007-12-20 08:51:22 · answer #2 · answered by David T 3 · 1⤊ 1⤋