If "logb(x)" means "log base b of x" and if b is any base, what is logb(1)?

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2007-12-20 08:34:54 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Suppose, logb(x) = y.
This means, b^y = x.
Here, x = 1, so y = ?
Now, b^y = 1 is true for any value of 'b' if and only if y = 0.
So, logb(1) = 0.

2007-12-20 08:38:04 · answer #1 · answered by psbhowmick 6 · 1⤊ 0⤋

Log10 100 = 2
10Â² = 100

log2 8 = 3
2Â³ = 8

logb 1 = 0
b^0 = 1

2007-12-24 15:31:38 · answer #2 · answered by Como 7 · 0⤊ 0⤋

log base b a = c means

b^c = a

so...

log base b 1 = x

b^x = 1

x = 0

b^0 = 1

Hope this helps!

2007-12-20 16:39:23 · answer #3 · answered by disposable_hero_too 6 · 0⤊ 0⤋