math help, help with what you can PLEASE!!!?

Question

1. What is the inverse of the equation y = 5x + 1?

2. In the ordered pair (x, y), the value of y is a member of the ___________.

3. What is the slope of the line for the equation x = 5?

4. Put the equation in slope-intercept form and identify the slope of the line. 9x + 6y = 3

5. a) What is the slope of the line through the points (5, 2) and (5, -3)?

b) Describe the line through these points.

6. Change the given equation into slope-intercept form. 3x + 4y = 12

7. What is the value of g[f(3)] for the functions f(x) = 3x – 5 and g(x) = x + 1?

8. Given the domain values { -2, 0, 2 }, find the range values for the function y = 3x + 2.

9. What is the value of f(6) for the function f(x) = 3x – 5?

Answer 1

I'll do these with explanations of how to do them.
1. To find the inverse of y = 5x+1
a). Swap x and y: x = 5y+1
b). Now solve for y: x-1 = 5y
y = (x-1)/5.
2. Range? Not sure what this one is asking.
3. This is a vertical line, so its slope is undefined.
4. Just solve for y:
9x + 6y = 3
3x + 2y = 1
2y = -3x + 1
y = -3/2 + 1/2. The slope is -3/2.

5. (From now on, just a few hints)
How do you compute slope of a line through 2 points?
What happens here? What kind of line have you got?
6. Solve for y.
7. f(3) = 3*3-5 = 4. How do you get g(4).
8. Plug in each x and compute the corresponding y.
The range values are -4, 2 and 8.
9. Plug 6 into the equation for f(x) and grind out
the answer.
Hope that helps!

Answer 2

3. undefined
5. (-3-2)/(5-5)= -5/0 infinite or undefined. To describe the line draw the y and the x axis, plug the point and draw the line where they intercepted. The line will be parallel to y axis pass throug point 5 on the x axis.
9. f(6)= 3*6-5=13
7.f(3)= 3*3-5=4 then, g[f(3)]=13+1=14
4.slope int-form of 9x + 6y=3
The equation is Y=mx + b then, 6y= -9x +3
y=(-9x+3)/6
Y= -3/2x +1/2 is the slope intercept form. The slope is -3/2
6. #6 is the same procedure as # 4.

Here is an example follow this example to solve #1. I gotta go I gotta go and good luck.

Write y = f(x) and solve for x.
Here,
y = x1/3 + 2 gives:
x1/3 = y - 2,
whence x = (y - 2)3.
Switch x and y in the resulting equation. The resulting function of x is the inverse.
Switching x and y gives
y = (x - 2)3.
Thus the inverse function is
f-1(x) = (x - 2)3.

Answer 3

1) y=5x+1
x=5y+1
x-1=5y
(x-1)/5 =y
f^(-1) =(x-1)/5

2) range

3)The slope is undefined since that is a vercial line.

4) 6y=-9x +3
y=(-9/6)x +3/6
y=(-3/2)x +1/2
Slope = -.3/2

5) m=(2-(-3))/(5-5)
=5/0
Slope is undefined since diviision by zero is undefined.
b) Vertical line

6) 4y =-3x+12
y=(-3/4)x +12/3
y=(-3/4)x +4

7) g(f(x)) = 3x-5+1
=3x-4
f(f(3)) = 3(3) -4
=9-4
=5

8) y=3(-2) +2
=-6+2
=-4
y=3(0)+2
=2
y=3(2) +2
=6+2
=8
{=-4, 2,8}

9) f(6) =3(6)-5
=18-5
=13

Answer 4

Hi,
1. replace y->x and x->y
x=5y+1
y=1/5·(x-1)
3.pending=90º = pi/2
4. 6y=3-9x
y=3/6-9/6·x
y= -3/2·x+1/2, standar equion y=mx+b
slope = -3/2, intercept=1/2
5. m=(y1-y2)/(x1-x2)=(2-(-3))/(5-5)=5/0=oo
if m=tan(s)=00, then s=90º, vertical line
6. see 4
7. f(3)=3·3-5 = 4
g(f(3))=g(5)=5+1=6
8. domains is range of X values, then
x=2, y= 3·2+2=8
x=0, y=3·0+2=2
x=-2, y=3·-2+2=-4
f: {-2,0,2}:{-4,2,8}
9. replace in f(x)=3x – 5, X by 6
f(6)=3·6-5=13

luck,

Answer 5

4. y=-3/2x+1/3 slope is -3/2
5a. undefined
b. vertical
6. y=-3/4x+3
9. 13