I need help with finding the rate/order of reaction. The question I need help with is:
Rate expression is 2SO2 + O ---> 2SO3
rate = k[SO2]^2[O]
What is the overall order of reaction?
It would be excellent if someone could explain HOW to find the overall order of reaction so I can complete the rest of the questions I have.
2007-12-20 07:40:11 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
rate = k[SO2]^2[O2]^1
The overall order of reaction is the sum of the powers. that is 2 + 1 = 3.
3 is the overall order of reaction.
NB When the power/index number is NOT shown it is read as one(1). So in your expression you have written [O], if you re-write it as '[O2]^1', the index number is now clear,so to find the order of reaction just add the power nummbers.
NNB Sometimes in these rate equations you may find a conc'n to zero order '[conc]^0'. From your mathematiics anything the power 'zero' = 1. so '[conc]^0 = 1
2007-12-20 08:03:10 · answer #1 · answered by lenpol7 7 · 5⤊ 0⤋
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2016-12-15 18:36:45 · answer #2 · answered by ? 4 · 0⤊ 0⤋
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2016-10-03 07:46:19 · answer #3 · answered by ? 4 · 0⤊ 0⤋
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Chemistry - Rate/Order of Reaction?
I need help with finding the rate/order of reaction. The question I need help with is:
Rate expression is 2SO2 + O ---> 2SO3
rate = k[SO2]^2[O]
What is the overall order of reaction?
It would be excellent if someone could explain HOW to find the overall order of reaction so I can complete...
2015-08-19 05:04:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The equation is 2SO2 + O2 ===> 2SO3
The rate law is rate = k[SO2]^2[O2]
The reaction is third order, because three objects have to come together simultaneously in order for the reaction to happen. You know that, because all three objects are found in the rate law.
2007-12-20 07:45:36 · answer #5 · answered by steve_geo1 7 · 5⤊ 0⤋