9.
Write 6x3 – 48x2 + 90x in factored form.
a.
6x(x – 5)(x + 3)
b.
–3x(x – 5)(x + 6)
c.
–5x(x + 6)(x – 3)
d.
6x(x – 3)(x – 5)
2007-12-20 06:29:37 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6x³ - 48x² + 90x = 0
Common factor
6x(x² - 8x + 15) = 0
The middle term inside the parenthesis is - 8x
The first term x² = 1
Find the sum of the middle term
Multiply the first term 1 times the last term 15 equals 15 and factor.
Factors of 15
1 x 15
3 x 5. . .←. ,.Use these factors
- 5x and - 3x satisfy the sum of the middle term
Insert - 5x and - 3x into the equation
6x(x² - 8x + 15) = 0
6x(x² - 5x - 3x + 15) = 0
Group factor inside the parenthesis
6x(x² - 5x) - (3x + 15) = 0
6x[x(x - 5) - 3(x - 5)] = 0
6x(x - 3)(x - 5) = 0
- - - - - - - -
The answer is D.
- - - - - - -s-
2007-12-20 07:31:35 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
For increasing cubic binomials the prevalent formulation is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D
2016-11-23 17:45:25 · answer #2 · answered by ? 4 · 0⤊ 0⤋
6x^3 -48x^2 +90x
First, look to see if you can factor any common term out
in this problem: 6x can
rewrite
6x*(x^2 - 8x + 15)
6x(x -5)(x -3)
D
2007-12-20 07:03:41 · answer #3 · answered by Sheep Herder 3 · 0⤊ 0⤋
6x(x^2-8x+15)
6x(x-5)(x-3)
2007-12-20 06:41:43 · answer #4 · answered by Nur S 4 · 0⤊ 0⤋
6*x*(x-3)*(x-5)
D
2007-12-20 06:35:37 · answer #5 · answered by Bob Williams 2 · 0⤊ 0⤋
6x^3-48x^2+90x
=6x(x^2-8x+15)
=6x(x-5)(x-3).ANS.
2007-12-20 07:06:29 · answer #6 · answered by Anonymous · 0⤊ 0⤋