Finding intercepts?

Question

how would you find the x and y intercept of the equation...

2x+3y=12

Answer 1

X intercept: Let y = 0.

2x + 3(0) = 12
2x = 12
x = 6

Therefore the x intercept is (6, 0)

Y intercept: Let x = 0.

2(0) + 3y = 12
3y = 12
y = 4

Therefore the y intercept is (0, 4)

Answer 2

The y-intercept is the value of y where the graph intercepts the x axis, i.e., when x = 0.
Similarly, x-intercept is the value of x where the graph intercepts the y axis, or y = 0.
http://i233.photobucket.com/albums/ee195/DWRead/Josh-A.jpg

To find the y-intercept, replace the x in the equation by 0.
2x + 3y = 12
2•0 + 3y = 12
3y = 12
y = 4
∴ y-intercept is 4.

To find the y-intercept, replace the y in the equation by 0.
2x + 3y = 12
2x + 3•0 = 12
2x = 12
x = 6
∴ x-intercept is 6.

Answer 3

if x=0 3y=12 y=4 intercept on y=4

for y=0 2x=12 x=6 intercept on x= 6