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5 answers

No. What makes you think there might be?

Escape velocity is not a vector; it is scalar.

2007-12-20 04:00:23 · answer #1 · answered by laurahal42 6 · 0 0

No there isn't. A rocket can leave the atmosphere anywhere. The point where it leaves the atmosphere is only guided by the path it must take to reach its final destination (either in orbit at a certain point, or to rendezvous with another spacecraft, or some distant body in the solar system).

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2007-12-20 11:39:36 · answer #2 · answered by tlbs101 7 · 2 0

No, but there is an advantage to taking off from near the equator. You are trying to get your rocket up to escape velocity - fast enough that it will stay up. You can use the spin of the planet to help, and the ground is spinning faster at the equator than anywhere else.

2007-12-20 11:42:29 · answer #3 · answered by nowaynohow 7 · 2 0

only in that there's a 'window of opportunity' where it's best for the rocket to be passing thru in order to hit, or hookup where it's heading for.......

2007-12-20 12:05:48 · answer #4 · answered by meanolmaw 7 · 0 0

PBS did a show on this last night!

2007-12-20 11:40:41 · answer #5 · answered by Anonymous · 0 0

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