English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

convert the polar equation to rectangular form

r=3cosThaida

2007-12-20 03:11:51 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

r = 3 cos θ
r^2 =3r cos θ
x^2 + y^2 = 3x
x^2 + y^2 - 3x = 0

If you prefer y as a function of x:
y = ±sqrt(3x-x^2)

2007-12-20 03:34:53 · answer #1 · answered by markhamnr 2 · 1 0

Convert the polar equation to rectangular form.
r = 3cosθ
________

Remember the identities.

x = rcosθ
y = rsinθ
x² + y² = r²
_________

r = 3cosθ
r² = 3rcosθ
x² + y² = 3x
x² - 3x + y² = 0
(x² - 3x + 9/4) + y² = 9/4
(x - 3/2)² + y² = 9/4

This is the equation of a circle with center (3/2,0) and radius 3/2.

2007-12-21 13:57:39 · answer #2 · answered by Northstar 7 · 1 0

x=r cos(theta)
y=r sin(theta)
From polar to rectangular:
r=sqrt(x^2+y^2)
theta=arctan(y/x)
r=3 cos(theta)
sqrt(x^2+y^2)=3
square both sides
x^2+y^2=9 is the rectangular form.

2007-12-20 03:26:29 · answer #3 · answered by cidyah 7 · 0 2

fedest.com, questions and answers