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1. Find the product (x^2+2)X^2+3)

2. Simplify the expression (x^2y^3divided by2^z)^4

3. Divide the expression (12x^2y^2+6x^2y-15xy^2) divided by 3xy

2007-12-20 01:55:53 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Prob 01:

(x^2 + 2)(x^2 + 3)

ans. [ x^4 + 5x^2 + 6 ]



Prob 02:

{ (x^2)(y^3) / (2^z) } ^4

ans. [ (x^8)(y^12) / (2^4z) ]




Prob 03:

(12x^2)(y^2) + (6x^2)(y) - (15x)(y^2) / 3xy

ans. [ 4xy + 2x - 5y ]

2007-12-20 02:01:14 · answer #1 · answered by RYAN 3 · 0 0

1. I think you mean

(x^2+2)(x^2+3)=x^4+2x^2+3x^2+6

=x^4+5x^2+6

You simply multiply everything on the left with everything on the right

2. Is this what you mean??

(x^2*y^3/z^2)^4=x^8*y^12/z^8

or (x^2*y^3/z^2)^4=x^8*y^12*z^-8


Yours would be (x^2*y^3/2^z)^4=x^8*y^12/2^4z
You just multiply every power with 4

3.(12x^2y^2+6x^2y-15xy^2)/3xy

=4xy+2x-5y




You divide numbers with numbers and variables with the same variables. So 12x^2y^2/3xy=12/3*x^2/x*y^2/y=4xy

If you need more explanation add it like detail.

2007-12-20 10:10:12 · answer #2 · answered by Santras 3 · 0 0

(x^2 + 2)(x^2 + 3) = x^4 + 5x^2 + 6

(x^2y^3 / 2^z)^4 = x^8y^12 / 2^4z

12x^2y^2 + 6x^2y - 15xy^2 / 3xy =
4xy + 2x - 5y

2007-12-20 10:04:27 · answer #3 · answered by Steve A 7 · 0 0

1.
(x^2+2)(x^2+3)
x^4 +5x^2 +6


2.
((x^2y^3)/2^z)^4

x^8y^12/2^4z

(x^8)(y^12)(2^-4z)

(16^-z)(x^8)(y^12)

3.
(12x^2y^2 +6x^2y -15xy^2)/3xy
3xy(4xy +2x -5y)

2007-12-20 10:27:35 · answer #4 · answered by justforfun_1811 3 · 0 0

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