What is the solution of the following liner system?
2y + 6x = -24
y - 13x = -12
a) (0, -12)
b) 0
c) (0, 3)
d) infinite number of solutions
2007-12-20 01:44:16 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If you double the 2nd equation the only difference with the 1st will be in the x coordinate. That means x=0. Substituing x=0 gives y=-12 in both equations so y=-12
So the answer is a --> (0,-12)
2007-12-20 01:50:30 · answer #1 · answered by Astral Walker 7 · 0⤊ 0⤋
This can be solved by cancellation. Multiply the second by 2 so they match up:
2y + 6x = -24
2y - 26x = -24 to make the y's cancel, subtract the like terms
0y + 32x = 0
32x=0
x=0
now to find y. Put this x into either of the original (I'll use the second)
y - 13*0 = -12
y = -12
so the answer is a) (x,y) = (0,-12)
2007-12-20 09:53:13 · answer #2 · answered by JG 5 · 0⤊ 0⤋
find y in terms of x in the 2nd equation:
y=13x-12
Substitute into the 1st.
2(13x-12) + 6x = -24
26x-24 + 6x = -24
26x+6x=0
42x=0
x=0
Then use that in the second equation
y - 13 (0) = -12
y = -12
x=0, y=-12 That's a)
QED
2007-12-20 09:55:19 · answer #3 · answered by Ken 7 · 0⤊ 0⤋
(-1)
(2)
-2y-6x=24
2y-26x=-24
-32x=0
x=0 y=-12
so, a)
2007-12-20 09:50:39 · answer #4 · answered by Claire W 2 · 0⤊ 0⤋
You actually need help to find out the intersection of two straight lines!?
2007-12-20 09:56:30 · answer #5 · answered by jimmy_siddhartha 4 · 0⤊ 0⤋
If I calculated correctly:
a) (0,12)
2007-12-20 09:52:16 · answer #6 · answered by la_lluvia_06 2 · 0⤊ 0⤋