How do I simplify [3(5-a)/2a] / [3(a-5)/4(a+1]?

Answer 1

3 (5 - a) (4) (a + 1)
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(2a) (3) (a - 5)


(-12) (a - 5) (a + 1)
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(6a) (a - 5)

- 2 (a + 1) / a

Answer 2

Start by multiplying the 3(5-a) = 3*5 - 3a ...then u divide the answer by 2a...Once your done with the first brackets, you move to the second set [3(a-5)/4(a+1)].. again you start multiplying 3(a-5) then u multiply 4(a+1)...like this : 4*a + 4*1. The second bracket simplified should come out 3a-15/ 4a+1
The first bracket simplified should come out 15-3a/2a...then just divide the answer of the first bracket with the answer of the second bracket...AND WOOLAH!

Answer 3

Remember, to divide is to multiply by the reciprocal. Therefore you want to "flip" the divisor and change it to multiplication. When it's a multiplication problem, you can cancel like factors. You'll be able to cancel the 3's, reduce the 2 and 4, and the (5-a) and (a-5) differ by a factor of one. It will look like this:

[3(5-a)/2a] [4(a+1)/3(a-5)]

= -2(a+1)/a

that's it! :)

Answer 4

[(15-3a)/2a) / [(3a -15)/ (4a +1)]
= [(15-3a)/2a) * [(4a+1)/ (3a-15)] change the sign, and switch the denominator up.
= [(15-3a)/2a) *[-(4a+1)/(15-3a)] reverse the sign by moving the negative out.
=(1/2a)*(-(4a+1))
=-(1/2a) * (4a+1)
=-(4a+1)/2a
=-2 1/2a