I think I know how to solve for this but when I check my answer it's incorrect. What I do is place (4/3) on both sides to cancel out (3/4) then I divide both sides by 2 and get 322.5. However, when I plug it into 2x^(3/4) I don't get 128.
2007-12-19 18:37:09 · 6 answers · asked by georgie0515 1 in Science & Mathematics ➔ Mathematics
Thats your problem... you are exponentiating both sides by 4/3 first... dont
Divide by 2 first
2007-12-19 18:43:48 · answer #1 · answered by Anonymous · 1⤊ 3⤋
If 2x^(3/4) = 128, then x^(3/4) = 64. So x^(1/4) = 4, and x = 256.
2007-12-20 02:49:12 · answer #2 · answered by Anonymous · 1⤊ 2⤋
1st you should devide both sides by 2
x^(3/4) = 64
raise to power 4/3
x= 64*(4/3) = (4^3)^(4/3) = 4^4 = 256
2007-12-20 02:44:54 · answer #3 · answered by Mein Hoon Na 7 · 1⤊ 2⤋
2 x ^ (3/4) = 128
x ^ (3/4) = 64
( x ^ (3/4) ) ^ (4/3) = ( 64 ) ^ (4/3)
x ^ 1 = ( 2 ^ 6 ) ^ ( 4/3 )
x = 2 ^ ( 6 * 4 / 3 )
. = 2 ^ ( 8 )
. = 128
2007-12-20 02:53:49 · answer #4 · answered by Ben 3 · 0⤊ 3⤋
x^(3/4) = 64
x = 64^ (4/3)
x = 4^4
x = 256
2007-12-20 03:02:47 · answer #5 · answered by Como 7 · 4⤊ 1⤋
i've never tried methods that u used(replacing things when it comes to squaring)
2^(0.75) is not the same as 2^(~`~~~~~)
use what the text book showed u.its better rather than using your own method. :)
2007-12-20 02:48:49 · answer #6 · answered by zar~ 2 · 0⤊ 3⤋