Find the Axis of symetry y=x^2-5x+3?

2 ⤊

2007-12-19 17:14:53 · 3 answers · asked by ☆♥ C&ice♥☆ 2 in Science & Mathematics ➔ Mathematics

y = (x² - 5x + 25/4) - 25/4 + 3
y = (x - 5/2)² - 25/4 + 12/4
y = (x - 5/2)² - 13/4

Axis of symmetry is x = 5/2

2007-12-19 19:26:44 · answer #1 · answered by Como 7 · 2⤊ 0⤋

Axis of symetry has a formula x = - b/2a

y=x^2-5x+3

b = -5
a = 1

Axis of symetry x = --5/2= 2.5
x = 2.5

2007-12-20 02:11:25 · answer #2 · answered by mlam18 6 · 0⤊ 0⤋

x=2.5 is the axis of symmetry

use completing the square method. u will get a parabola with vertex at (2.5, -13/4)

y = (x^2 -5x +25/4) +3 - 25/4

2007-12-20 01:23:22 · answer #3 · answered by jet l 1 · 0⤊ 1⤋