The word "solve" suggests an equation which , in turn , requires an = sign:-
m ² + 2 m - 15 = 0
( m + 5 ) ( m - 3 ) = 0
m = - 5 , m = 3
2007-12-19 21:47:59
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answer #1
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answered by Como 7
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You can factor the expression into
(m+5)(m-3)
but you cannot "solve" it without it equaling anything. If it was supposed to equal zero, then you take the above factorization and set each part equal to zero.
m+5=0 m-3=0
m=-5 or m=3
2007-12-19 16:00:53
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answer #2
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answered by Zαrα Mikαzuki 6
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It depends on what the equation is set equal to, but for my explanation it will be zero.
m^2+2m-15=0
First factor the equation.
(m+5)(m-3)=0
Set term equal to zero and solve for m.
m+5=0
m= -5
m-3=0
m= 3
The answer can be either 3 or -5 (only if the function is equal 0)
2007-12-19 16:02:53
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answer #3
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answered by Anonymous
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m2 + 2m - 15
=(m+5)(m-3)
2007-12-19 15:57:24
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answer #4
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answered by DANIEL G 6
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(m+5)(m-3) factor the 15
2007-12-19 15:57:50
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answer #5
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answered by Timothy C 2
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2m + m2 - 15 = 4m - 15
If ur trying to solve for m, then i guess M would have to equal 15/4
Oh.. is that a squared? o.o u should have used ^ for ur exponent.. =P Daniels got it then, factor it
2007-12-19 15:56:55
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answer #6
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answered by 港式奶茶 3
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you can't... it's not an equation, you need an equals (=) somewhere
You can simplify it by combining like terms (m), in which case you would have 4m - 15
2007-12-19 15:57:40
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answer #7
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answered by Anonymous
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if u want to factor it..it is
(m+5)(m-3)
2007-12-19 16:14:17
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answer #8
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answered by WordIsBond 5
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solve what? the above expression equated to zero or what? your question is incomplete!
2007-12-19 15:57:31
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answer #9
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answered by Nterprize 3
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Hey man! this is algebra not chemistry
2016-04-10 08:56:10
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answer #10
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answered by Anonymous
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