Study Guide Help!?

Question

I really need help for a test tomorrow, so if somebody could assist me in figuring this out I'd appreciate it.

A 5.037 g piece of iron heated to 100 degrees Celcius is placed in a coffee up calorimeter that initially contains 27.3 g of water at 21.2 degrees Celcius. If the final temp. is 22.7 degrees Celcius, what is the specific heat capacity of the iron (J/g C)?

Answer 1

the key formula is q = mCp delta T.

realize that the heat given up by the hot iron is gained by the cool water. So make 2 equations and set them equal to each other.

The Cp of water is 4.184 J/g oC. You have all the other data. Plug in and solve for the Cp of iron

you