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The position of a car is given by the values in the following table. Find the average velocity for the time period begining when t=2 and lasting 2 seconds

t(seconds) s(feet)
0 0
1 18
2 35
3 74
4 110
5 175



a.) 35.5
b.)47.5
c.)39
d.)37.5
e.)33.5

Average velocity always messes me up is there some kind of formula? Thanks

2007-12-19 13:54:04 · 2 answers · asked by mastriannichris 1 in Education & Reference Homework Help

2 answers

velocity = distance / speed

distance = end - start
distance = 110 - 35
distance = 75 feet

time = 2 seconds

velocity =75 feet / 2 seconds
velocity = 37.5 ft/sec

2007-12-19 14:11:37 · answer #1 · answered by disposable_hero_too 6 · 0 0

you got me on this one, but i do know, it's not the "trans-linear vector principal" constant acceleration to mid point,with equal, constant de-acceleration to end point.

2007-12-19 14:01:34 · answer #2 · answered by oneemazingplace 3 · 0 0

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