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need help with these problems, my physics teacher is evil and when people asks for help he says its physics your not supposed to get it. Please show work so i know how and explain to people

1. In tackling a running back from the other team, a defensive lineman exerts a force of 500N at 180*, while a linebacker simultaneously applies a force of 650N at 270*. What is the resultant force on the carrier?

1. 1 force of 60N and a 2nd of 30N act on an object at point P. Add the vectors and find the magnitude of the resultant at 30*,45*,&60*

2007-12-19 13:48:15 · 1 answers · asked by deathgod197 3 in Science & Mathematics Physics

1 answers

Sorry to hear your teacher is not willing to explain in more depth.

Both of these problems involve vectors in 2-dimensional space.
They are always solved by looking at the x and y components separately and then using sqrt sum of the squares to find magnitude. Use atan(y/x) to find the angle.

Running back:
x components:
500*cos(180)=-500
650*cos(270)=0
so the x is -500

y components:
500*sin(180)=0
650*sin(270)=-650
so the y is -650

the angle is atan(-650/-500)
or 52.43 degrees west of south

the resultant magnitude is
sqrt(650^2+500^2)
820 N

For the point P, is the angle the angle of separation between the forces? I will assume yes and always have the 60 N on the x axis
30 degrees
x=60+30*cos(30)
x=85.98
y=30*sin(30)=15
the resultant is
sqrt(85.98^2+15^2)
87.28 N

45 degrees
x=60+30*cos(45)
x=81.21
y=30*sin(45)=21.21
the resultant is
sqrt(81.21^2+21.21^2)
83.93 N

60 degrees
x=60+30*cos(60)
x=75
y=30*sin(60)=25.98
the resultant is
sqrt(75^2+25.98^2)
79.37 N

j

2007-12-20 04:21:59 · answer #1 · answered by odu83 7 · 0 0

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