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Question

I need a wee bit of help s'il vous plait!! Lol
This is just a little bit of my home work that I am having trouble
with & if someone can explain this much to me I think I can
figure out the rest of my worksheet like this!
Please & Thank You!!


1)What products would CaCl2 + NaC18H33O2 form?

2)What ratio of drops of equal molarity would give you the largest volume of precipitate?(goes with problem #1)(please explain this!!)

3)Which of the following mixtures will make the largest amount of precipitate? Explain your reasoning.

(A) 100 mL 1.0 M AgNO3 +200 mL 1.0 M CaCl2
(B) 200 mL1.0M AgNO3 + 100 mL 1.0 M CaCl2
(C) 150 mL 1.0M AgNO3 + 50 mL 1.0 M CaCl2
(D) 50 mL 1.0 M AgNO3 + 150 mL 1.0 M CaCl2

Answer 1

yes!

1.
Ca(C18H33O2)2 + 2NaCl

2. one drop CaCl2 and two drops of NaC18H33O2

3. b because it has the highest number of moles of both the reactants.

Answer 2

1. Ca(C18H33O2)2 + 2 NaCl

2. In the balanced equation, you would have a 2 in front of the NaC18H33O2. So, you need to have 2 times as many moles of that reactant as you do CaCl2. So a ratio of 1 drop CaCl2 to 2 drops NaC18H33O2 would give you the maximum precipitate.

3. Here, too, when you balance the equation, you will have:
2 AgNO3 + CaCl2 --> Ca(NO3)2 + 2 AgCl(s)

So, since all of the molarities are the same, you will need a ratio of 2:1 by volume of Ag(NO3)2:CaCl2 to give you the maximum amount of precipitate. That would make (B) the best answer.