54ab^3/81a^3b^2
(^=to the power of)
the answer can be
2/9 ab
or
2/3 ab
or
2a/3b
or
6/7 ab
2007-12-19 11:11:49 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
It simplifies to:
(54.a.b.b.b)/(81.a.a.a.b.b)...cancel by 27:
(2.a.b.b.b)/(3.a.a.a.b.b)....cancel by a:
(2.b.b.b)/(3.a.a.b.b)....cancel by b^2:
2b/3a^2.
Which is not one of the answers given. Are you sure that you have copied everything down correctly ? ? ?
Hope this helps, Twiggy.
2007-12-19 11:24:09 · answer #1 · answered by Twiggy 7 · 0⤊ 0⤋
None are correct... the correct answer is:
(2b) / (3a^2)
Hope this helps!
2007-12-19 11:18:59 · answer #2 · answered by disposable_hero_too 6 · 0⤊ 0⤋
You should probably start by expanding the problem:
54*a*b*b*b
_________
81*a*a*a*b*b
Cancel out like terms and you should know where to go from there.
2007-12-19 11:26:06 · answer #3 · answered by birdieboy 3 · 0⤊ 0⤋
54 ab^3
-----------
81a^3 b^2
2b/ 3a^2
2007-12-19 11:39:22 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
i agree with that answer..
2b / (3a^2)
2007-12-19 11:22:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋