x+2(x+4)=1+3(x+2) i think i understand it, but when i complete i end up with 7=8, is it possible not to be able to solve this kind of equation? don' t be mean, im not that stupid, i swera
2007-12-19 11:07:03 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Expanding out you get:
x + 2x + 8 = 1 + 3x + 6
3x + 8 = 3x + 7
0x = -1
(or you could have rearranged it as 7 = 8 or 8 = 7, it doesn't matter)
You are correct, if you have written the brackets where they are supposed to be, there is no solution for this equation.
2007-12-19 11:11:05 · answer #1 · answered by Jacob A 5 · 1⤊ 0⤋
x+2(x+4)=1+3(x+2)
x + 2x + 8 = 1 + 3x + 6
3x + 8 = 3x + 7
8 = 7
This is not an equation since the two parts are not equal. It cannot be solved.
.
2007-12-19 19:17:08 · answer #2 · answered by ? 7 · 0⤊ 0⤋
you wrote: x+2(x+4)=1+3(x+2)
For this equation, there is no solution.
if i had to guess based on my experience, I would say that you meant to write:
(x+2)(x+4)=1+3(x+2)
in which case:
x^2 + 6x + 8 = 1 + 3x + 6
x^2 + 3x + 1 = 0
After applying the quadratic formula, you get that
x = (-3 +/- sqrt (9 - 4)) / 2
x = ( -3 - sqrt(5) ) / 2 OR x = (sqrt(5) - 3) / 2
2007-12-19 19:15:57 · answer #3 · answered by hariseshadri 2 · 0⤊ 0⤋
x+2(x+4)=1+3(x+2)
This is neither a conditional equation nor an identity.
Since, it's neither of the two, then there is no equation to solve.
teddy boy
2007-12-19 19:28:01 · answer #4 · answered by teddy boy 6 · 0⤊ 0⤋
x+2x+8=1+3x+6
3x+8=7+3x
8=7
maybe the equation is wrong
2007-12-19 19:12:53 · answer #5 · answered by Omega 3 · 0⤊ 1⤋
I got the same results as you, so there is no solution. What does the question say exactly?
2007-12-19 19:12:21 · answer #6 · answered by DWRead 7 · 0⤊ 0⤋