( ^ = to the power of )
8x^3-4x^2y^3-12xy/4x^2y^2
the answer can be
2xy-y- 3x/y ; y doesnt = 0
or
2x/y -y -3xy ; y doesnt = 0
or
2x-y- 3/xy ; x&y dont = 0
or
2x/y -y- 3/xy ; x&y dont = 0
thank you im sorry if this is confusing but im confused to lol :)
2007-12-19 10:48:13 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Well, it has to be x and y both not equal to 0. Think about it.
As for the rest -- you really need to use parentheses when you write questions like this. Sorry.
2007-12-19 17:38:05 · answer #1 · answered by Curt Monash 7 · 0⤊ 0⤋
the 1st one is actual. you need to simplify each and each expression to is base factors. Then take out the factors on magnificent and backside that are the comparable. Then for the exception checklist what might make the denominator = 0 it is the fee of x that it does no longer prepare to. m^2-m-20 --------------- m^2+7m+12 (m-5)(m+4) ---------------- (m+4)(m+3) m-5 ------ m+3 yet m might desire to no longer equivalent -4 or -3 The third answer divide by 4 simply by fact it may come out of the two the magnificent and backside, and there are no exceptions. the subsequent one ingredient out x+3 out of the two to offer you 2x+a million ------ 2x+2 and x might desire to no longer equivalent -a million or -3 and 5 ingredient out n+a million to offer you n+a million ----- 10 n might desire to no longer equivalent -a million in spite of the shown fact that.
2016-11-23 16:00:37 · answer #2 · answered by ? 4 · 0⤊ 0⤋